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Proof step 1 from proof numabs-01 (conclusion)
0 ≤ j, 0 ≤ j0 ⊦ 0 < i → abs(i * (* j) + (* j0)) = i * j + j0
Special step normalize
And obtained the following new goals
Proof step 2
:
0 ≤ j, 0 ≤ j0 ⊦ 0 < i → abs(i * j + j0) = i * j + j0