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Proof step 3 from proof numle-07 (previous step)

⊦ i1 * j ≤ j ↔ 0 ≤ (1 - i1) * j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ i * j = j * i
Proof step 5:
⊦ j * i1 ≤ j ↔ 0 ≤ (1 - i1) * j

Rule argument

spec: int-mult inst: name: commutativity seq: ⊦ i * j = j * i subst: [i, j] → [j, i1] flags: rewrite, current

Additional information

Used terms: j, i1