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Proof step 3 from proof square-eq-01 (previous step)

i < j, i * i + i = j * j + j, 0 ≤ i, 0 ≤ j ⊦ i = j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
i * i + i = j * j + j, i < j, 0 ≤ i, 0 ≤ j, 0 < j ⊦ i = j

Rule argument

Additional information

Used simplifier rules: forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs