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Proof step 22 from proof square-eq (previous step)

i = ~ abs(j), i + abs(j) = 0, i < 0 ⊦ i * i = j * j, j = 0

User applied rule insert equation

And obtained the following new goals

Proof step 23:
~ abs(j) + abs(j) = 0, ~ abs(j) < 0 ⊦ ~ abs(j) * ~ abs(j) = j * j, j = 0

Rule argument

pos: left 1 flags: discard

Additional information