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Proof step 26 from proof square-eq (previous step)

¬ i < 0, i = abs(j) ⊦ i * i = j * j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 27:
⊦ abs(j) * abs(j) = j * j

Rule argument

Additional information

Used simplifier rules: absls: ⊦ ¬ abs(i) < 0; from specification int-abs