[Imprint]
[Data Privacy Statement]
[E-Mail]
View
long theorem info
. View
the proof
. Back to
main index
. View
the specification
. View
theorem base summary
, View
theorem base listing
, the
used properties by spec
, the
dependency list
, the
symbol table
,
Proof step 4 from proof square-even (
previous step
)
(∃ j. i = 2 * j) ∨ (∃ j. i = 2 * j + 1), i * i + i = 2 * j + 1 ⊦
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 5
:
i * i + i = 2 * j + 1, i = 2 * j0 ∨ i = 2 * j1 + 1 ⊦
Rule argument
Additional information