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Proof step 2 from proof square-gez-02 (previous step)

i + i * i < 0 ⊦

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ abs(i) ≤ i * i
Proof step 4:
abs(i) ≤ i * i, i + i * i < 0 ⊦

Rule argument

spec: int-mult inst: name: square-le-02 seq: ⊦ abs(i) ≤ i * i subst: [i] → [i] flags: current, []

Additional information

Used terms: i