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Proof step 5 from proof square-le-02 (previous step)

i * i < abs(i) ⊦ abs(i) ≤ abs(i) * abs(i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs