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Proof step 5 from proof square-le-04 (previous step)

i * i + i ≤ j * j + j, 0 ≤ i, 0 ≤ j ⊦ ¬ j < i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ i + j = j + i
Proof step 7:
i + i * i ≤ j * j + j, 0 ≤ i, 0 ≤ j ⊦ ¬ j < i

Rule argument

spec: int-basic2 inst: name: add-c seq: ⊦ i + j = j + i subst: [j, i] → [i, i * i] flags: rewrite

Additional information

Used terms: i, i * i