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Proof step 1 from proof square-le-06 (conclusion)

⊦ i * i ≤ i + 1 ↔ ¬ ¬(i = 0 ∨ i = 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ i * i ≤ i + 1 ↔ i = 0 ∨ i = 1

Rule argument

Additional information