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Proof step 3 from proof square-le-06 (previous step)

i * i ≤ i + 1 ⊦ i = 0 ∨ i = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
i * i ≤ i + 1 ⊦ i = 0, i = 1

Rule argument

Additional information