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Proof step 2 from proof square-le (previous step)

i * i ≤ j * j ⊦ abs(i) ≤ abs(j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i * i ≤ j * j, abs(j) < abs(i) ⊦

Rule argument

Additional information

Used simplifier rules: lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs