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Proof step 3 from proof square-ls-02 (
previous step
)
i * i + i < j * j + j, 0 ≤ i, 0 ≤ j ⊦ i < j
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 4
:
i * i + i < j * j + j, 0 ≤ i, 0 ≤ j ⊦ i < j
Rule argument
Additional information