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Proof step 5 from proof square-ls-02 (previous step)

j + j * j ≤ j + i * i, i * i + i < j * j + j, 0 ≤ i, 0 ≤ j ⊦ i < j

User applied rule cut formula

And obtained the following new goals

Proof step 6:
j + j * j ≤ j + i * i, i * i + i < j * j + j, 0 ≤ i, 0 ≤ j ⊦ i + i * i < j + i * i, i < j

Rule argument

fma: i + i * i < j + i * i

Additional information

Used simplifier rules: ls-01: ⊦ i + j < i + i0 ↔ j < i0; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2 Used formulas: i + i * i < j + i * i