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Proof step 10 from proof square-ls (previous step)

abs(i) < abs(j) ⊦ i * i < j * j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
abs(i) < abs(j), j * j ≤ i * i ⊦

Rule argument

Additional information

Used simplifier rules: lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs