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Proof step 3 from proof square-ls (previous step)

i * i < j * j ⊦ abs(i) < abs(j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
i * i < j * j, abs(j) ≤ abs(i) ⊦

Rule argument

Additional information

Used simplifier rules: lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs