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Proof step 6 from proof square-ls (previous step)

abs(j) * abs(j) ≤ abs(i) * abs(i), i * i < j * j, abs(j) ≤ abs(i) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ abs(i * j) = abs(i) * abs(j)
Proof step 8:
abs(j * j) ≤ abs(i) * abs(i), i * i < j * j, abs(j) ≤ abs(i) ⊦

Rule argument

spec: int-mult inst: name: abs-eqall seq: ⊦ abs(i * j) = abs(i) * abs(j) subst: [j, i] → [j, j] flags: rewrite, current

Additional information

Used terms: j, j