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Proof step 1 from proof square-one-le (conclusion)
⊦ i * i ≤ 1 ↔ i = 0 ∨ i = 1 ∨ i = ~1
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 2
:
⊦ i * i ≤ 1 ↔ i = 0 ∨ i = 1 ∨ i = ~1
Rule argument
Additional information