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Proof step 3 from proof square-one-le (
previous step
)
i * i ≤ 1 ⊦ i = 0 ∨ i = 1 ∨ i = ~1
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 4
:
i * i ≤ 1 ⊦ i = 0, i = 1, i = ~1
Rule argument
Additional information