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Proof step 6 from proof succ-lsplit (previous step)

j0 = i0 +1, ∀ i. (i + 1) * j0 = i * j0 + j0 ⊦ (i + 1) * i0 + 1 = i * i0 + j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: succ-rsplit: ⊦ i * (j + 1) = i * j + i;%add-c: ⊦ i + j = j + i; from specification int-basic2%add-in: ⊦ i + j = i + i0 ↔ j = i0; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%succ-01: ⊦ i +1 = i + 1; from specification int-basic2