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Proof step 1 from proof zero-eq (conclusion)

⊦ i * j = 0 ↔ i = 0 ∨ j = 0

User applied rule case distinction

And obtained the following new goals

Proof step 2:
i * j = 0 ⊦ i = 0 ∨ j = 0

Rule argument

pos: right 1

Additional information

Used simplifier rules: zero-left: ⊦ 0 * i = 0;%associativity: ⊦ i * j * j0 = (i * j) * j0;%commutativity: ⊦ i * j = j * i;