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Proof step 1 from proof zero-ge-add (conclusion)

⊦ 0 ≤ j1 ∧ j1 < j → (0 ≤ i0 * j + j1 ↔ 0 ≤ i0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 ≤ j1, j1 < j, 0 < j ⊦ 0 ≤ i0 * j + j1 ↔ 0 ≤ i0

Rule argument

Additional information

Used simplifier rules: forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs