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Proof step 1 from proof zero-left (conclusion)

⊦ 0 * i = 0

Heuristic structural induction applied rule structural induction

And obtained the following new goals

Proof step 2:
0 * i0 = 0 ⊦ 0 * i0 -1 = 0

Rule argument

term: i

Additional information

Used simplifier rules: succ-rsplit: ⊦ i * (j + 1) = i * j + i;%int generated by 0, +1, -1;;%succ-01: ⊦ i +1 = i + 1; from specification int-basic2%add-zero: ⊦ i + 0 = i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2%add-c: ⊦ i + j = j + i; from specification int-basic2