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Proof step 1 from proof zero-ls-03 (conclusion)

⊦ i ≤ 0 → (i * j < 0 ↔ ¬ ¬(0 < j ∧ i ≠ 0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i ≤ 0 ⊦ i * j < 0 ↔ 0 < j ∧ i ≠ 0

Rule argument

Additional information

Used simplifier rules: forward-le-04: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward) from specification int-abs