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Proof step 11 from proof dec-int-01 (previous step)

m % 2 = 0, 2 * i→n(i) = m + 1, i < 0 ⊦ i = 0, n→i(m / 2) = i

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: nat-div inst: name: modex seq: ⊦ n ≠ 0 → (m % n = 0 ↔ (∃ n0. m = n0 * n)) subst: [n, m] → [2, m] flags: rewrite

Additional information

Used simplifier rules: modeq-01: ⊦ n0 < n → (m * n + n0 = m0 * n ↔ m = m0 ∧ n0 = 0); from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult%mult-c: ⊦ m * n = n * m; from specification nat-mult%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic2%c: ⊦ m + n = n + m; from specification nat-basic2 Used terms: 2, m