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Proof step 8 from proof add-eq2pot-01 (
previous step
)
⊦ 0 ≤ j ∧ 0 ≤ i ∧ 0 ≤ i0 → (2 ^ i = 2 ^ i0 + j ↔ j = 2 ^ i0 * (2 ^ (i - i0) - 1) ∧ i0 ≤ i)
Lemma
add-eq2pot