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Proof step 1 from proof div-div-rec (conclusion)

⊦ j < 0 ∧ 0 < i → ((j - (2 ^ i - 1)) / 2 ^ i - 1) / 2 = (j - (2 ^ (i + 1) - 1)) / 2 ^ (i + 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
j < 0, 0 < i ⊦ ((j + 1 - 2 ^ i) / 2 ^ i - 1) / 2 = (j + 1 - 2 ^ (i + 1)) / 2 ^ (i + 1)

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%sub-sub-04: ⊦ i - (j - j0) = i + j0 - j; from specification int-abs