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Proof step 7 from proof div-div-rec (previous step)

j + 1 = 2 ^ i * (i0 + 1) + j0, 0 ≤ i, i0 < i, i0 ≤ 0, j0 < i, j0 ≤ 0, j + 1 < 2 ^ i, abs(j0) < 2 ^ i, 0 < i, j < 0 ⊦ (i0 - 1) / 2 = (j + 1 - 2 ^ i * 2) / (2 ^ i * 2)

User applied rule insert equation

And obtained the following new goals

Proof step 8:
j + 1 = 2 ^ i * (i0 + 1) + j0, 0 ≤ i, i0 < i, i0 ≤ 0, j0 < i, j0 ≤ 0, 2 ^ i * (i0 + 1) + j0 < 2 ^ i, abs(j0) < 2 ^ i, 0 < i, j < 0 ⊦ (i0 - 1) / 2 = (2 ^ i * (i0 + 1) + j0 - 2 ^ i * 2) / (2 ^ i * 2)

Rule argument

pos: left 1 flags:

Proof step 7 from proof div-div-rec (previous step)

User applied rule insert equation

And obtained the following new goals

Rule argument

Additional information