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Proof step 3 from proof div-twopot (previous step)

i = i0 + j, 0 ≤ i, 0 ≤ j ⊦ 2 ^ i / 2 ^ j = 2 ^ i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
0 ≤ j, 0 ≤ i0 + j ⊦ 2 ^ (i0 + j) / 2 ^ j = 2 ^ i0

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs