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Proof step 2 from proof div2-2pot-neg (previous step)

i < j, i < 0, 0 < j, i + 1 < j ⊦ (i * 2 ^ j) / 2 = i * 2 ^ (j - 1)

User applied rule cut formula

And obtained the following new goals

Proof step 3:
i = ~ abs(i), i < j, i < 0, 0 < j, i + 1 < j ⊦ (i * 2 ^ j) / 2 = i * 2 ^ (j - 1)

Rule argument

fma: i = ~ abs(i)

Additional information

Used simplifier rules: abs-08: ⊦ i < 0 → abs(i) = ~ i; from specification int-abs%neg-02: ⊦ ~ ~ i = i; from specification int-abs Used formulas: i = ~ abs(i)