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Proof step 1 from proof div2-2pot (conclusion)

⊦ 0 ≤ i ∧ 0 ≤ j → (j / 2 ^ i) / 2 = j / 2 ^ (i + 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 ≤ i, 0 ≤ j ⊦ (j / 2 ^ i) / 2 = j / (2 ^ i * 2)

Rule argument

Additional information

Used simplifier rules: succ: ⊦ 0 ≤ i → j ^ (i + 1) = j ^ i * j;%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2