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Proof step 1 from proof divmod2-2pot-neg (conclusion)

⊦ j < 0 ∧ 1 < i → ((j % 2 ^ i - 1) / 2) % 2 = ((j - 1) / 2) % 2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
j < 0, 0 < i, 1 < i ⊦ ((j % 2 ^ i - 1) / 2) % 2 = ((j - 1) / 2) % 2

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-pos: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward) from specification int-basic1