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Proof step 15 from proof divmod2-2pot-neg (previous step)

j0 < i, j0 ≤ 0, i0 * 2 ^ i + j0 < 0, abs(j0) < 2 ^ i, 1 < i, 0 < i, 0 ≤ i, i0 < 0 ⊦ ((j0 - 1) / 2) % 2 = ((j0 - 1) / 2 + i0 * 2 ^ (i - 1)) % 2, i0 = 0, (i0 * 2 ^ (i - 1)) % 2 = 0 ∧ j0 < 0

User applied rule cut formula

And obtained the following new goals

Proof step 16:
j0 = 0, j0 < i, j0 ≤ 0, i0 * 2 ^ i + j0 < 0, abs(j0) < 2 ^ i, 1 < i, 0 < i, 0 ≤ i, i0 < 0 ⊦ ((j0 - 1) / 2) % 2 = ((j0 - 1) / 2 + i0 * 2 ^ (i - 1)) % 2, i0 = 0, (i0 * 2 ^ (i - 1)) % 2 = 0 ∧ j0 < 0
Proof step 19:
j0 < i, j0 ≤ 0, i0 * 2 ^ i + j0 < 0, abs(j0) < 2 ^ i, 1 < i, 0 < i, 0 ≤ i, i0 < 0 ⊦ j0 = 0, ((j0 - 1) / 2) % 2 = ((j0 - 1) / 2 + i0 * 2 ^ (i - 1)) % 2, i0 = 0, (i0 * 2 ^ (i - 1)) % 2 = 0 ∧ j0 < 0

Rule argument

fma: j0 = 0

Additional information

Used formulas: j0 = 0