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Proof step 8 from proof eq2 (previous step)

1 / 2 ^ ~ i = 2, i < 0 ⊦ i = 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ 1 < j → 1 / j = 0

Rule argument

spec: int-div inst: name: one-04 seq: ⊦ 1 < j → 1 / j = 0 subst: [j] → [2 ^ ~ i] flags: rewrite

Additional information

Used simplifier rules: pot2-pos-01: ⊦ 1 < 2 ^ i ↔ 0 < i;%neg: ⊦ 0 < ~ i ↔ i < 0; from specification int-abs%zero-gels-01: ⊦ i < 0 ∧ 0 ≤ j → i < j; from specification int-abs Used terms: 2 ^ ~ i