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Proof step 11 from proof equal-minus-one (previous step)

i ^ j = ~1, i ≠ 0 ∨ 0 < j ⊦ i = ~1, j = 0

User applied rule cut formula

And obtained the following new goals

Proof step 12:
i ^ j = ~1, i ≠ 0 ∨ 0 < j ⊦ i = 0, i = ~1, j = 0

Rule argument

fma: i = 0

Additional information

Used simplifier rules: zero-01: ⊦ 0 < j → 0 ^ j = 0; Used formulas: i = 0