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Proof step 23 from proof equal-minus-one (previous step)

abs(i ^ i0) = 1, i + i ^ i0 = 0, 0 < i0 ⊦ i0 = 0, i = 0, i = ~1

User applied rule cut formula

And obtained the following new goals

Proof step 24:
i ^ i0 = ~ i, abs(i ^ i0) = 1, i + i ^ i0 = 0, 0 < i0 ⊦ i0 = 0, i = 0, i = ~1

Rule argument

fma: i ^ i0 = ~ i

Additional information

Used simplifier rules: negeq: ⊦ ~ i = j ↔ i + j = 0; from specification int-abs Used formulas: i ^ i0 = ~ i