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Proof step 26 from proof equal-minus-one (previous step)

i ^ i0 = ~ i, abs(i ^ i0) = 1, i + i ^ i0 = 0, 0 < i0 ⊦ i < 0, i0 = 0, i = 0, i = ~1

User applied rule insert equation

And obtained the following new goals

Proof step 27:
i ^ i0 = ~ i, abs(~ i) = 1, i + ~ i = 0, 0 < i0 ⊦ i < 0, i0 = 0, i = 0, i = ~1

Rule argument

pos: left 1 flags:

Additional information