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Proof step 29 from proof equal-minus-one (previous step)

j < 0, 1 / i ^ abs(j) = ~1 ⊦ i = 0, i = ~1, j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 30:
1 / i ^ ~ j = ~1, j < 0 ⊦ i = 0, i = ~1, j = 0

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%abs-08: ⊦ i < 0 → abs(i) = ~ i; from specification int-abs