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Proof step 32 from proof equal-minus-one (previous step)

¬(0 < i ^ ~ j ∧ i ^ ~ j ≤ 1), 1 / i ^ ~ j = ~1, j < 0 ⊦ i = 0, i = ~1, j = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 33:
1 / i ^ ~ j = ~1, j < 0, i ^ ~ j ≤ 0 ⊦ j = 0, i = ~1, i = 0

Rule argument

Additional information

Used simplifier rules: forward-le-04: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward) from specification int-abs%numleledel: j0 ≠ 0, j ≤ j0 ⊦ i ≤ (* j) → i ≤ (* j0); from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs%one-04: ⊦ 1 < j → 1 / j = 0; from specification int-div%lels-01: ⊦ ¬ i ≤ j ↔ j < i; from specification int-abs