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Proof step 35 from proof equal-minus-one (previous step)

1 / i ^ ~ j = ~1, j < 0, i ^ ~ j < 0 ⊦ j = 0, i = ~1, i = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 36:
⊦ j < 0 → i / (* j) = ~(i / ~ j)
Proof step 37:
i ^ ~ j < 0, ~(1 / ~(i ^ ~ j)) = ~1, j < 0, i ^ ~ j < 0 ⊦ j = 0, i = ~1, i = 0

Rule argument

spec: int-div inst: name: num-neg-01 seq: ⊦ j < 0 → i / (* j) = ~(i / ~ j) subst: [j, i] → [i ^ ~ j, 1] flags: rewrite

Additional information

Used terms: i ^ ~ j, 1