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Proof step 46 from proof equal-minus-one (previous step)

abs(i ^ ~(j + 1)) = 1, i + i ^ ~(j + 1) = 0, j < 0 ⊦ i = 0, i = ~1, j = 0

User applied rule cut formula

And obtained the following new goals

Proof step 47:
i ^ ~(j + 1) = ~ i, abs(i ^ ~(j + 1)) = 1, i + i ^ ~(j + 1) = 0, j < 0 ⊦ i = 0, i = ~1, j = 0

Rule argument

fma: i ^ ~(j + 1) = ~ i

Additional information

Used simplifier rules: negeq: ⊦ ~ i = j ↔ i + j = 0; from specification int-abs Used formulas: i ^ ~(j + 1) = ~ i