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Proof step 50 from proof equal-minus-one (previous step)

abs(j) % 2 = 1 ⊦ ~1 ^ j = ~1, j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 51:
⊦ 0 < j ∧ j % 2 = 1 → ~1 ^ j = ~1
Proof step 52:
¬(0 < j ∧ j % 2 = 1), abs(j) % 2 = 1 ⊦ ~1 ^ j = ~1, j = 0

Rule argument

spec: inst: name: minus-one-odd seq: ⊦ 0 < j ∧ j % 2 = 1 → ~1 ^ j = ~1 subst: [j] → [j] flags: rewrite, current

Additional information

Used terms: j