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Proof step 6 from proof equal-minus-one (previous step)

~1 ^ j = ~1 ⊦ j = 0, abs(j) % 2 = 1

User applied rule cut formula

And obtained the following new goals

Proof step 7:
~1 ^ j = ~1 ⊦ 0 < j, j = 0, abs(j) % 2 = 1

Rule argument

fma: 0 < j

Additional information

Used simplifier rules: minus-one-even: ⊦ 0 < j ∧ j % 2 = 0 → ~1 ^ j = 1;%abs-16: ⊦ 0 < j → abs(j) = j; from specification int-abs%mod-two-06: ⊦ 0 < i → (i % 2 ≠ 1 ↔ i % 2 = 0); from specification int-div Used formulas: 0 < j