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Proof step 23 from proof exin2pot (previous step)

0 < i0, 0 < 2 ^ i, 0 < i0 * 2 + j1, i0 < 2 ^ i * 2, 2 ^ i ≤ i0, 0 ≤ i, 0 ≤ i0, j1 < 2, 0 ≤ j1, 1 < 2 ^ i * 2, ∀ j0. i→n(j0) < i→n(i0 * 2 + j1) → 0 < j0 → (∃ i. 0 ≤ i ∧ 2 ^ i ≤ j0 ∧ j0 < 2 ^ (i + 1)) ⊦ 2 ^ i * 2 ≤ i0 * 2 + j1, i0 * 2 + j1 = 0, i0 * 2 + j1 = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 24:
0 < i0, 0 < 2 ^ i, 0 < i0 * 2 + j1, i0 < 2 ^ i * 2, 2 ^ i ≤ i0, 0 ≤ i, 0 ≤ i0, j1 < 2, 0 ≤ j1, 1 < 2 ^ i * 2, ∀ j0. i→n(j0) < i→n(i0 * 2 + j1) → 0 < j0 → (∃ i. 0 ≤ i ∧ 2 ^ i ≤ j0 ∧ j0 < 2 ^ (i + 1)) ⊦ i0 * 2 + j1 = 0, i0 * 2 + j1 = 1, 2 ^ i * 2 ≤ i0 * 2 + j1

Proof step 23 from proof exin2pot (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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