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Proof step 5 from proof exinpot (previous step)

1 < i, 0 < i, ∀ j0, i. i→n(j0) < i→n(1) → 0 < j0 ∧ 1 < i → (∃ i0. 0 ≤ i0 ∧ i ^ i0 ≤ j0 ∧ j0 < i ^ (i0 + 1)) ⊦ ∃ i0. 0 ≤ i0 ∧ i ^ i0 ≤ 1 ∧ 1 < i ^ i0 * i

User applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: 0 abort: F discard: F computed: F

Additional information

Used simplifier rules: Pot-zero: ⊦ j ^ 0 = 1;%one: ⊦ 1 * i = i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult Used terms: 0