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Proof step 1 from proof geom-mod (conclusion)

⊦ i ≠ 1 ∧ 0 ≤ j → (1 - i ^ j) % (1 - i) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 ≤ j ⊦ (1 - i ^ j) % (1 - i) = 0, i = 1

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs