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Proof step 11 from proof geom-mod (previous step)

1 - i ^ i0 * i = (1 - i ^ i0) * i - (i - 1), (1 - i ^ i0) % (1 - i) = 0, 0 ≤ i0, ∀ j0, i. i→n(j0) < i→n(i0 + 1) → 0 ≤ j0 → (1 - i ^ j0) % (1 - i) = 0 ∨ i = 1 ⊦ i = 1, ~1 = i0, (1 - i ^ i0 * i) % (1 - i) = 0

User applied rule insert equation

And obtained the following new goals

Proof step 12:
(1 - i ^ i0) % (1 - i) = 0, 0 ≤ i0, ∀ j0, i. i→n(j0) < i→n(i0 + 1) → 0 ≤ j0 → (1 - i ^ j0) % (1 - i) = 0 ∨ i = 1 ⊦ i = 1, ~1 = i0, ((1 - i ^ i0) * i - (i - 1)) % (1 - i) = 0

Rule argument

pos: left 1 flags: discard

Proof step 11 from proof geom-mod (previous step)

User applied rule insert equation

And obtained the following new goals

Rule argument

Additional information