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Proof step 17 from proof le-pos (previous step)

0 < i ∧ 0 ≤ i0, 2 ≤ i, 1 < i, ~2 < i0, ~1 ≤ i0, 0 ≤ i0, ∀ j1, i, j0. i→n(j1) < i→n(i0 +1) → 2 ≤ i ∧ 0 ≤ j1 ∧ 1 < i → (i ^ j1 ≤ i ^ j0 ↔ j1 ≤ j0) ⊦ false ↔ i0 + 1 ≤ 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
0 < i, 2 ≤ i, 1 < i, ~2 < i0, ~1 ≤ i0, 0 ≤ i0, i0 + 1 ≤ 0, i0 + 1 ≤ i0, ∀ j1, i, j0. i→n(j1) < i→n(i0 +1) → 2 ≤ i ∧ 0 ≤ j1 ∧ 1 < i → (i ^ j1 ≤ i ^ j0 ↔ j1 ≤ j0) ⊦

Rule argument

Additional information

Used simplifier rules: forward-lele: ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1; (forward) from specification int-abs