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Proof step 26 from proof le-pos (previous step)

¬ 1 < i ^ ~ j0, j0 ≤ i0, 2 ≤ i, 1 < i, ~2 < i0, 0 ≤ i0, ~1 ≤ i0, j0 < 0, j0 < i0, ∀ j1, i, j0. i→n(j1) < i→n(i0 +1) → 2 ≤ i ∧ 0 ≤ j1 ∧ 1 < i → (i ^ j1 ≤ i ^ j0 ↔ j1 ≤ j0) ⊦ j0 = 0, i ^ i0 * i ≤ 1 / i ^ ~ j0 ↔ i0 + 1 ≤ j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 27:
j0 ≤ i0, 2 ≤ i, 1 < i, ~2 < i0, 0 ≤ i0, ~1 ≤ i0, j0 < 0, j0 < i0, i ^ ~ j0 ≤ 1, i ^ ~ j0 < i, ∀ j1, i, j0. i→n(j1) < i→n(i0 +1) → 2 ≤ i ∧ 0 ≤ j1 ∧ 1 < i → (i ^ j1 ≤ i ^ j0 ↔ j1 ≤ j0) ⊦ j0 = 0, i ^ i0 * i ≤ 1 / i ^ ~ j0 ↔ i0 + 1 ≤ j0

Rule argument

Additional information

Used simplifier rules: forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs%lels: ⊦ ¬ i < j ↔ j ≤ i; from specification int-abs