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Proof step 1 from proof ls-2pot-01 (conclusion)

⊦ 0 ≤ i → (j * 2 ^ i < j0 * 2 ^ i ↔ j < j0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 ≤ i ⊦ j * 2 ^ i < j0 * 2 ^ i ↔ j < j0

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs